【高一数学】函数的计算题目》》》》

(1)x=4^(2/3)=2^(4/3)时,y=log(2)[2^2/2^(4/3)]*log(4)[4^(2/3)/4^(1/2)]=log(2)[2^(2/3)]*log(4)[4^(1/6)]=(2/3)*(1/6)=1/9(2)y=log(2)[4/x]*log(4)[x/2]=(log(2)[4]-log(2)[x])*(log(4)[x]-log(4)[2])=(2-t)*(t/2-1/2)=(-1/2)t^2+(3/2)t-1因为2