已知ab不等于1,且满足2a平方加2008a加3等于零和3b平方加2008b加2等于零,则

2a²+2008a+3=0------------------------------(1) 3b²+2008b+2=0------------------------------(2)(1)*b得：2a²b+2008ab+3b=0-------------------(3)(2)*a得：3ab²+2008ab+2a=0-------------------(4)(3)-(4)得：2a²b+3b-3ab²-2a=0 2a²b-2a-3ab²+3b=0 2a(ab-1)-3b(ab-1)=0 (ab-1)(2a-3b)=0 ab-1=0 ab=1(已知ab不等于1,所以ab=1不是方程组的解,舍去）2a-3b=0 a=3b/2 b=2a/3把a=3b/2代入(1)得：2(3/2b)²+2008(3b/2)+3=0 9b²/2+3012b+3=0 9b²+6024b+6=0 (3b)²+6024b+(1004)²-1008010=0 (3b+1004)²-(√1008010)²=0(3b+1004-√1008010) (3b+1004+√1008010)=0 3b+1004-√1008010=0 b1=(√1008010-1004)/3 3b+1004+√1008010=0 b2=(-√1008010-1004)/3把b1=(√1008010-1004)/3代入a=3b/2得：a1=(√1008010-1004)/2把b2=(-√1008010-1004)/3代入a=3b/2得：a2=(-√1008010-1004)/2