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计算：9^[log3(2)]-2[1+0.5log2(5)]

学习时间:2026-08-11 08:08:29 阅读：8374

计算：9^[log3(2)]-2[1+0.5log2(5)]

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自信的草丛

爱笑的猎豹

2026-08-11 08:08:29

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9^[log3(2)]-2[1+0。5log2(5)]=[3^log3(2)]^2-2[log2(2)+log2(5^0。5)]=2^2-2[log2(2*5^0。5)]=4-log2[2*5^0。5]^2=4-log2(20)

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怕黑的抽屉
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2026-08-11 08:08:29
9^[log3(2)]-2[1+0。5log2(5)]=[3^log3(2)]^2-2[log2(2)+log2(5^0。5)]=2^2-2[log2(2*5^0。5)]=4-log2[2*5^0。5]^2=4-log2(20)

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