



计算：9^[log3(2)]-2[1+0.5log2(5)]

学习时间:2026-05-14 01:40:29 阅读：7121

计算：9^[log3(2)]-2[1+0.5log2(5)]

最佳回答

活力的火

美丽的学姐

2026-05-14 01:40:29



9^[log3(2)]-2[1+0。5log2(5)]=[3^log3(2)]^2-2[log2(2)+log2(5^0。5)]=2^2-2[log2(2*5^0。5)]=4-log2[2*5^0。5]^2=4-log2(20)

最新回答共有2条回答

健壮的羊
回复
2026-05-14 01:40:29
9^[log3(2)]-2[1+0。5log2(5)]=[3^log3(2)]^2-2[log2(2)+log2(5^0。5)]=2^2-2[log2(2*5^0。5)]=4-log2[2*5^0。5]^2=4-log2(20)

热门文章

猜你喜欢