解关于x的不等式 log2(x-1)>log4[a(x-2)+1] (a>1).

定义域x-1>0,x>1a(x-2)+1>0x-2>-1/ax>2-1/aa>10log2[a(x-2)+1](x-1)^2>a(x-2)+1x^2-2x+1>ax-2a+1x^2-(a+2)+2a>0(x-2)(x-a)>0若1