化简[（x的平方－4）／(x的平方－4X+4)+(2-X)/(X＋2)]÷x/(x-2) 的结果是?

[（x的平方－4）／(x的平方－4X+4)+(2-X)/(X＋2)]÷x/(x-2)= [(x+2)(x-2)/(x-2)^2 -(x-2)/(x+2)] × (x-2)/x= [(x+2)/(x-2) -(x-2)/(x+2)] × (x-2)/x= [(x+2)^2 -(x-2)^2] / [(x+2)(x-2)] × (x-2)/x= 8x / [(x+2)(x-2) × (x-2)/x= 8 / (x+2)