y= √[x√(x√x)] + 1 / √[x√(x√x)] 怎么求导?

y= √[x√(x√x)] + 1 / √[x√(x√x)] 怎么求导?都是根号,一层包一层√[x√(x√x)] 就是 [ x 乘上 (x乘以根号x)开的根号 ]再开根