等差数列{an}中,a1,a2,a4恰好成等比数列,则a

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等差数列{an}中,a1,a2,a4恰好成等比数列,则a

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怕黑的香烟

坦率的天空

2026-03-30 19:16:02

设差数列{an}的公差为d,由a1,a2,a4恰好成等比数列,得:(a1+d)2=a1(a1+3d),整理得:d2=a1d.若d=0,则a1=a4,a1a4=1;若d≠0,则a1=d,a4=a1+3d=4a1,a1a4=14.故答案为:1或14.

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  • 愉快的钢笔
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    2026-03-30 19:16:02

    设差数列{an}的公差为d,由a1,a2,a4恰好成等比数列,得:(a1+d)2=a1(a1+3d),整理得:d2=a1d.若d=0,则a1=a4,a1a4=1;若d≠0,则a1=d,a4=a1+3d=4a1,a1a4=14.故答案为:1或14.

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