数学问题概率求解释Rework problem 28 from section 3.4 of your text, in

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数学问题概率求解释Rework problem 28 from section 3.4 of your text, involving the drawing of twoballs from a box of colored balls. Assume the box contains 8 balls:3 red, 3 blue, and 2 yellow. A ball is drawn and its color noted. If the ball is yellow, it is replaced; otherwise, it is not.A second ball is then drawn and its color is noted.What is the probability that the first ball was yellow, given that thesecond was red? KEY IS 7/27Anyone know the detailed process?Thax!

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搞怪的丝袜

慈祥的太阳

2026-08-10 18:50:48

首先算出来取出第二个求是红球的概率:3/8*2/7+3/8*3/7+2/8*3/8=81/(28*8)再算出第一次取出黄球第二次取出红球的概率:2/8*3/8=6/(8*8)6/(8*8)除以81/(28*8)就是7/27ps:中间数字太大我就没算结果了

最新回答共有2条回答

  • 大胆的宝马
    回复
    2026-08-10 18:50:48

    首先算出来取出第二个求是红球的概率:3/8*2/7+3/8*3/7+2/8*3/8=81/(28*8)再算出第一次取出黄球第二次取出红球的概率:2/8*3/8=6/(8*8)6/(8*8)除以81/(28*8)就是7/27ps:中间数字太大我就没算结果了

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