就这几道题,谢谢你了1 lim(1-[√(1+m)]/x) X趋向02 lim((x-3)/x-1) x趋向无穷3 y=

学习 时间:2026-03-30 15:48:21 阅读:2943
就这几道题,谢谢你了1 lim(1-[√(1+m)]/x) X趋向02 lim((x-3)/x-1) x趋向无穷3 y=x^2lnx 求 dy/dx4 ∫(5√(1+x^2)+2/(1+x^2))5 ∫((2x^2)+3/x^(2+1))/dx6 ∫((2x^2+3)/(x^2+1))dx7 ∫f(x)dx=e^xcos2x+c

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平常的月亮

俊秀的大碗

2026-03-30 15:48:21

1 lim(1-[√(1+m)]/x) X趋向0=∞2 lim((x-3)/x-1) x趋向无穷=13 y=x^2lnx 求 dy/dxdy/dx=y'dx=(2xlnx+x)dx4 ∫(5√(1+x^2)+2/(1+x^2))dx=∫5(1+x^2)^(-0。5)dx+∫2/(1+x^2)dx则原式=5ln(x+√1+x^2)+2arctanx+C5 ∫((2x^2)+3/x^(2+1))dx=∫2x^2dx+∫3/x^3dx=(1/3)x^3-(3/4)/x^4+C6 ∫((2x^2+3)/(x^2+1))dx=∫[2+1/x^2+1]dx=2x+arctanx+C7 ∫f(x)dx=e^xcos2x+cf(x)=[ ∫f(x)dx]'=(e^xcos2x+c)'=e^xcos2x-2e^xsin2x

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  • 无心的哈密瓜
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    2026-03-30 15:48:21

    1 lim(1-[√(1+m)]/x) X趋向0=∞2 lim((x-3)/x-1) x趋向无穷=13 y=x^2lnx 求 dy/dxdy/dx=y'dx=(2xlnx+x)dx4 ∫(5√(1+x^2)+2/(1+x^2))dx=∫5(1+x^2)^(-0。5)dx+∫2/(1+x^2)dx则原式=5ln(x+√1+x^2)+2arctanx+C5 ∫((2x^2)+3/x^(2+1))dx=∫2x^2dx+∫3/x^3dx=(1/3)x^3-(3/4)/x^4+C6 ∫((2x^2+3)/(x^2+1))dx=∫[2+1/x^2+1]dx=2x+arctanx+C7 ∫f(x)dx=e^xcos2x+cf(x)=[ ∫f(x)dx]'=(e^xcos2x+c)'=e^xcos2x-2e^xsin2x

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