分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)

{[(x²-4)/(x²-4x+4)]-(x-2)/(x+2)}/[x/(x-2)]=[(x+2)(x-2)/(x-2)²-(x-2)/(x+2)][(x-2)/x]=[(x+2)/(x-2)-(x-2)/(x+2)][(x-2)/x]=[(x+2)/(x-2)][(x-2)/x]-[(x-2)/(x+2)][(x-2)/x]=(x+2)/x-(x-2)²/x(x+2)=[(x+2)²-(x-2)²]/x(x+2)=[(x+2)-(x-2)][(x+2)+(x-2)]/x(x+2)=8x/x(x+2)=8/(x+2)很高兴为您解答,【学习宝典】团队为您答题。请点击下面的【选为满意回答】按钮,谢 再问： {[(x²-4)/(x²-4x+4)]+(2-x)/(x+2)}/[x/(x-2)]