数列 (16 0:36:31)

求 f(x) + f(1-x) f(x) = 1/(2^x + √2）f(1-x) = 1/[2^(1-x) + √2） 。(分子、分母同时乘以 2^x )= 2^x/(2 + √2 * 2^x) 。（分母中提取出 √2）= (2^x/√2) * (1/√2 + 2^x) = (2^x/√2) * f(x)f(x) + f(1-x)= (1+ 2^x/√2) * f(x)=[ (√2 + 2^x)/√2 ] * f(x)= [1/√2*f(x)] * f(x)= 1/√2f(-5)+f(-4)+…+f(0)+…+f(5)+f(6)= [f(-5) + f(6)] + [f(-4) + f(5)] + [f(-3) + f(4)] + [f(-2) + f(3)] + [f(-1) + f(2)] + [f(0) + f(1)]= 6/√2=3√2