函数f(X)=sin2x+2根号2cos(π/4+x)+3的值域.

学习 时间:2026-04-04 18:10:08 阅读:1139
函数f(X)=sin2x+2根号2cos(π/4+x)+3的值域.

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无聊的咖啡豆

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2026-04-04 18:10:08

f(X)=sin2x+2√2cos(π/4+x)+3=cos(2x-π/2)+2√2cos(π/4+x)+3=1-2sin²(x-π/4)-2√2sin(x-π/4)+3=4-2(sin²(x-π/4)+√2sin(x-π/4))=5-2(sin(x-π/4)+√2/2)²值域y∈[2-2√2,5]

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  • 高高的灰狼
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    2026-04-04 18:10:08

    f(X)=sin2x+2√2cos(π/4+x)+3=cos(2x-π/2)+2√2cos(π/4+x)+3=1-2sin²(x-π/4)-2√2sin(x-π/4)+3=4-2(sin²(x-π/4)+√2sin(x-π/4))=5-2(sin(x-π/4)+√2/2)²值域y∈[2-2√2,5]

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