活用公式变形求值 请详解

学习 时间:2026-04-02 16:52:14 阅读:1171
活用公式变形求值 请详解已知x^2-4x+1=0,求x的4次方+1/x^4的值?

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舒适的白猫

清秀的柠檬

2026-04-02 16:52:14

x^2-4x+1=0x-4+1/x=0x+1/x=4(x+1/x)^2=16x^2+1/x^2=14(x^2+1/x^2)^2=196x^4+1/x^4=196-2x^4+1/x^4=194

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  • 唠叨的黑猫
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    2026-04-02 16:52:14

    x^2-4x+1=0x-4+1/x=0x+1/x=4(x+1/x)^2=16x^2+1/x^2=14(x^2+1/x^2)^2=196x^4+1/x^4=196-2x^4+1/x^4=194

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