二倍角与半角的正弦、余弦和正切的题~

学习 时间:2026-04-04 19:38:53 阅读:7955
二倍角与半角的正弦、余弦和正切的题~1+cosa-sina 1-cosa-sina___________ + ____________ 怎么化简啊?1-cosa-sina 1+cosa-sina1+cosa-sina 1-cosa-sina ___________ + _____________________ 怎么化简啊?1-cosa-sina 1+cosa-sina

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俭朴的曲奇

简单的黑夜

2026-04-04 19:38:53

(1+cos(a)-sin(a))/(1-cos(a)-sin(a))+(1-cos(a)-sin(a))/(1+cos(a)-sin(a))首先通分,公分母为:(1-sin(a))^2-(cos(a))^2=1-2*sin(a)+(sin(a))^2-(cos(a))^2=2*(sin(a))^2-2*sin(a)=2*sin(a)*(sin(a)-1)第一项分子为:(1+cos(a)-sin(a))*(1+cos(a)-sin(a))=2-2*sin(a)+2*cos(a)-2*sin(a)*cos(a)第二项分子为:(1-cos(a)-sin(a))*(1-cos(a)-sin(a))=2-2*sin(a)-2*cos(a)+2*sin(a)*cos(a)两项相加为:4-4*sin(a)=-4*(sin(a)-1)再除以分母为:-2/(sin(a))即最终化简结果。

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  • 无语的微笑
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    2026-04-04 19:38:53

    (1+cos(a)-sin(a))/(1-cos(a)-sin(a))+(1-cos(a)-sin(a))/(1+cos(a)-sin(a))首先通分,公分母为:(1-sin(a))^2-(cos(a))^2=1-2*sin(a)+(sin(a))^2-(cos(a))^2=2*(sin(a))^2-2*sin(a)=2*sin(a)*(sin(a)-1)第一项分子为:(1+cos(a)-sin(a))*(1+cos(a)-sin(a))=2-2*sin(a)+2*cos(a)-2*sin(a)*cos(a)第二项分子为:(1-cos(a)-sin(a))*(1-cos(a)-sin(a))=2-2*sin(a)-2*cos(a)+2*sin(a)*cos(a)两项相加为:4-4*sin(a)=-4*(sin(a)-1)再除以分母为:-2/(sin(a))即最终化简结果。

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