因式分解 3,4,9,10

4a²-(1+a²-b²)²=(2a-1-a+b²)(2a+1+a-b²)=(a-1+b²)(3a+1-b²) x⁴+1/64=x⁴+1/4x²+1/64-1/4x²=(x²+1/8)²-1/4x²=(x²-1/2x+1/8)(x²+1/2x+1/8) c²+a(a-2c)-(a²+d²-b²-c²)²=c²+a²-2ac-(a²+d²-b²-c²)²=(a-c)²-(a²+d²-b²-c²)²=(a-c-a²-d²+b²+c²)(a-c+a²+d²-b²-c²) 4(ad+bc)²-(a²+d²-b²-c²)²=(2ad+2bc-a²-d²+b²+c²)(2ad+2bc+a²+d²-b²-c²)=[(b+c)²-(a-d)²][(a+d)²-(b-c)²]=(b+c-a+d)(b+c+a-d)(a+d-b+c)(a+d+b-c)