5/2×3×4+7/3×4×5+.+17/8×9×10+19/9×10×11怎么求

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5/2×3×4+7/3×4×5+.+17/8×9×10+19/9×10×11怎么求2013某工大附中入学题

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灵巧的银耳汤

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2026-04-08 23:37:39

∵5/(2×3×4)=(1/4)(1/2+1/3)=(1/2)(1/2-1/4)+1/3-1/4, 7/(3×4×5)=(1/5)(1/3+1/4)=(1/2)(1/3-1/5)+1/4-1/5, 9/(4×5×6)=(1/6)(1/4+1/5)=(1/2)(1/4-1/6)+1/5-1/6, 11/(5×6×7)=(1/7)(1/5+1/6)=(1/2)(1/5-1/7)+1/6-1/7, 13/(6×7×8)=(1/8)(1/6+1/7)=(1/2)(1/6-1/7)+1/7-1/8, 15/(7×8×9)=(1/9)(1/7+1/8)=(1/2)(1/7-1/9)+1/8-1/9, 17/(8×9×10)=(1/10)(1/8+1/9)=(1/2)(1/8-1/10)+1/9-1/10, 19/(9×10×11)=(1/11)(1/9+1/10)=(1/2)(1/9-1/11)+1/10-1/11。∴将上述8个等式左右分别相加,得:5/(2×3×4)+7/(3×4×5)+9/(4×5×6)+······+19/(9×10×11)=(1/2)(1/2+1/3-1/10-1/11)+1/3-1/11=1/4+(1/3)(1/2+1)-1/10-(1/11)(1/2+1)=1/4+1/2-1/10-3/22=3/4-1/10-3/22=(1/2)(3/2-1/5-3/11)=(1/2)[(15-2)/(2×5)-3/11]=(1/2)(13/10-3/11)=(1/2)(143-30)/110=113/220。 再问: 可以简便运算吗?有点看不懂 再答: 这就是简便运算了

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  • 犹豫的墨镜
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    2026-04-08 23:37:39

    ∵5/(2×3×4)=(1/4)(1/2+1/3)=(1/2)(1/2-1/4)+1/3-1/4, 7/(3×4×5)=(1/5)(1/3+1/4)=(1/2)(1/3-1/5)+1/4-1/5, 9/(4×5×6)=(1/6)(1/4+1/5)=(1/2)(1/4-1/6)+1/5-1/6, 11/(5×6×7)=(1/7)(1/5+1/6)=(1/2)(1/5-1/7)+1/6-1/7, 13/(6×7×8)=(1/8)(1/6+1/7)=(1/2)(1/6-1/7)+1/7-1/8, 15/(7×8×9)=(1/9)(1/7+1/8)=(1/2)(1/7-1/9)+1/8-1/9, 17/(8×9×10)=(1/10)(1/8+1/9)=(1/2)(1/8-1/10)+1/9-1/10, 19/(9×10×11)=(1/11)(1/9+1/10)=(1/2)(1/9-1/11)+1/10-1/11。∴将上述8个等式左右分别相加,得:5/(2×3×4)+7/(3×4×5)+9/(4×5×6)+······+19/(9×10×11)=(1/2)(1/2+1/3-1/10-1/11)+1/3-1/11=1/4+(1/3)(1/2+1)-1/10-(1/11)(1/2+1)=1/4+1/2-1/10-3/22=3/4-1/10-3/22=(1/2)(3/2-1/5-3/11)=(1/2)[(15-2)/(2×5)-3/11]=(1/2)(13/10-3/11)=(1/2)(143-30)/110=113/220。 再问: 可以简便运算吗?有点看不懂 再答: 这就是简便运算了

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