已知(x05-1)分之(1-3x)=(x+1)分之M+(x-1)分之N,求M、N的值

已知(x²-1)分之(1-3x)=(x+1)分之M+(x-1)分之N,求M、N的值(x²-1)分之(1-3x)=(x+1)分之M+(x-1)分之N(1-3x)/(x-1)(x+1)=(mx-m+nx+n)/(x-1)(x+1)∴1-3x=x(m+n)+(n-m)m+n=-3n-m=1∴m=-2n=-1