matlab随机矩阵乘法及点的显示?

学习 时间:2026-04-09 01:34:49 阅读:5813
matlab随机矩阵乘法及点的显示?x1——x7是我已经定义了的随机变量矩阵1*10000for i=1:10000A1=[1 0 cos(x6(i)) 0;sin(x6(i)) 0 -cos(x6(i)) 0;0 1 0 0;0 0 1 1]A2=[0 -1 0 0;1 0 0 x1(i);0 0 1 x2(i);0 0 0 1]A3=[1 0 0 x3(i);0 1 0 0;0 0 1 0;0 0 0 1]A4=[-cos(pi/4) sin(pi/4) 0 -(x4(i)).*cos(pi/4);-sin(pi/4) -cos(pi/4) 0 -(x4(i)).*sin(pi/4);0 0 1 0;0 0 0 1]A5=[cos(x7(i)) 0 -cos(x7(i)) 0;sin(x7(i)) 0 cos(x7(i)) 0;0 -1 0 0;0 0 0 1]A6=[1 0 0 0;0 1 0 0;0 0 1 x5(i);0 0 0 1]end现在我想用T=(A1)*(A2)*(A3)*(A4)*(A5)*(A6)得到10000个T,并用 plot3(T(1,4),T(2,4),T(3,4),'r*') 把这10000个点显示出来?请问该怎么办?

最佳回答

迷人的世界

纯真的纸鹤

2026-04-09 01:34:49

x1=1:10000; x2=1:10000; x3=1:10000; x4=1:10000; x5=1:10000; x6=1:10000; x7=1:10000;for i=1:10000A1=[1 0 cos(x6(i)) 0;sin(x6(i)) 0 -cos(x6(i)) 0;0 1 0 0;0 0 1 1];A2=[0 -1 0 0;1 0 0 x1(i);0 0 1 x2(i);0 0 0 1];A3=[1 0 0 x3(i);0 1 0 0;0 0 1 0;0 0 0 1];A4=[-cos(pi/4) sin(pi/4) 0 -(x4(i))。*cos(pi/4);-sin(pi/4) -cos(pi/4) 0 -(x4(i))。*sin(pi/4);0 0 1 0;0 0 0 1];A5=[cos(x7(i)) 0 -cos(x7(i)) 0;sin(x7(i)) 0 cos(x7(i)) 0;0 -1 0 0;0 0 0 1];A6=[1 0 0 0;0 1 0 0;0 0 1 x5(i);0 0 0 1];T=(A1)*(A2)*(A3)*(A4)*(A5)*(A6);figure(1); plot3(T(1,4),T(2,4),T(3,4),'-r*') ; grid on; hold on;end

最新回答共有2条回答

  • 潇洒的向日葵
    回复
    2026-04-09 01:34:49

    x1=1:10000; x2=1:10000; x3=1:10000; x4=1:10000; x5=1:10000; x6=1:10000; x7=1:10000;for i=1:10000A1=[1 0 cos(x6(i)) 0;sin(x6(i)) 0 -cos(x6(i)) 0;0 1 0 0;0 0 1 1];A2=[0 -1 0 0;1 0 0 x1(i);0 0 1 x2(i);0 0 0 1];A3=[1 0 0 x3(i);0 1 0 0;0 0 1 0;0 0 0 1];A4=[-cos(pi/4) sin(pi/4) 0 -(x4(i))。*cos(pi/4);-sin(pi/4) -cos(pi/4) 0 -(x4(i))。*sin(pi/4);0 0 1 0;0 0 0 1];A5=[cos(x7(i)) 0 -cos(x7(i)) 0;sin(x7(i)) 0 cos(x7(i)) 0;0 -1 0 0;0 0 0 1];A6=[1 0 0 0;0 1 0 0;0 0 1 x5(i);0 0 0 1];T=(A1)*(A2)*(A3)*(A4)*(A5)*(A6);figure(1); plot3(T(1,4),T(2,4),T(3,4),'-r*') ; grid on; hold on;end

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