关于X^7—1的因式分解 在复数范围内

先求:X^7—1=0的7个根。X1=1X2=cos(2PI/7)+i*sin(2PI/7)X3=cos(4PI/7)+i*sin(4PI/7)X4=cos(6PI/7)+i*sin(6PI/7)X5=cos(8PI/7)+i*sin(8PI/7)X6=cos(10PI/7)+i*sin(10PI/7)X7=cos(12PI/7)+i*sin(12PI/7)X^7—1=(x-X1)*(x-X2)*(X-X3)*(X-X4)*(X-X5)*(X-X6)*(X-X7)=(X-1)*[X-cos(2PI/7)+i*sin(2PI/7)]*[X-cos(4PI/7)+i*sin(4PI/7)]*[X-cos(6PI/7)+i*sin(6PI/7)]*[X-cos(8PI/7)+i*sin(8PI/7)]*[X-cos(10PI/7)+i*sin(10PI/7)]*[X-cos(12PI/7)+i*sin(12PI/7)]