x^2(x^2+5x-6)-(x^2+8x+12)=0

学习时间:2026-04-08 22:59:36 阅读：6475

x^2(x^2+5x-6)-(x^2+8x+12)=0求X的值

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2026-04-08 22:59:36

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x^2(x+6)(x-1)-(x+6)(x+2)=0提取公因式：(x+6)(x^3-x^2-x-2)=0(x+6)(x-2)(x^2+x+1)=0判断恒正因式：(x^2+x+1)>(x^2+x+1/4)=(x+1/2)^2>0x+6=0 or x-2=0原方程解集X={-6,2}