如图,在△ABC中,点D、E分别是△ABC的边AB,AC上的点,且AD=3,AE=6,DE=5,BD=15,CE=3,B

学习时间:2026-08-23 08:21:29 阅读：5268

如图,在△ABC中,点D、E分别是△ABC的边AB,AC上的点,且AD=3,AE=6,DE=5,BD=15,CE=3,BC=15,根据以上条件,你认为∠B=∠AED吗?

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2026-08-23 08:21:29

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解AB=AD+BD=3+15=18AC=AE+EC=6+3=9在△AED和△ABC中,AE/AB = 6 / 18 =1/3ED/BC = 5 /15 =1/3AD/AC =3/9 =1/3则△AED∽△ABC∠B=∠AED