求导 y=ln [x+(1+x²)½ ]

学习时间:2026-04-08 00:27:12 阅读：9949

求导 y=ln [x+(1+x²)½ ]y'=1/ [x+(1+x²)½ ] × [1+1/2×(1-x²)½]×(-2x)×（-2）看了前章居然不会求导了,后面这个-2 到底要不要拿出来.现在咋会出现到底要不要继续导啊~我这是怎么了?.求救我今天不正常了。o(╯□╰)o 上面正负号都写错

敏感的乌龟

2026-04-08 00:27:12

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有问题,是不需要的!y'=ln [x+(1-x²)½ ]'=1/[x+(1-x²)½ ]× [x+(1-x²)½ ]‘=1/[x+(1-x²)½ ]× [1+1/2×(1-x²)½(1-x^2)’]=1/[x+(1-x²)½ ]× [1+1/2×(1-x²)½(-2x)]