函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2

学习时间:2026-04-04 16:21:52 阅读：9884

函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2若当x∈[π/12,7π/12]时,f(x)的反函数为f//(x),求f//(1)的值.化简出来是2sin(2x+π/3)

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2026-04-04 16:21:52

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利用反函数定义f//(1)=a表明f(a)=1即2sin(2a+π/3)=1sin(2a+π/3)=1/22a+π/3=2kπ+π/6 或者 2kπ+5π/6,k是整数即2a=2kπ-π/6 或者 2kπ+π/2a=kπ-π/12 或者 kπ+π/4因为π/12