设集合M=﹛x|x²-2x-3≤0﹜,N=﹛x|x²+x+1＞0﹜,则M∩N=

x²-2x-3≤0(x-3)(x+1)≤0-1≤x≤3∴M={x|-1≤x≤3}x²+x+1＞0x²+x+1/4+3/4=(x+1/2)²+3/4恒>0∴x∈R即N=RM∩N=M={x|-1≤x≤3}