1+3+5=9 1+3+5+7=16 1+3+5+7+9=25 问你从一这样加到2007等于多少

1+3+5=[(1+5)/2]^2=3^2=91+3+5+7=[(1+7)/2]^2=4^2=161+3+5+7+9=[(1+9)/2]^2=5^2=25。1+3+5+7+。+2007=[(1+2007)/2]^2=1004^2=10080161+3+5+7+。+(2n-1)=[(1+2n-1)/2]^2=n^2