二次根号计算题/////

1-2a+a的平方/a-1-根号a的平方-2a+1/a的平方-a=（a-1)^2/(a-1)-根号（a-1)^2/(a^2-a)=a-1-(a-1)/(a-1)a=a-1-1/aa=1/2+根号3 a-1-1/a=根号3-1/2-2/(2根号3+1）=根号3-1/2-2(2根号3-1)/11=7根号3/11-7/22