1/(x+1)(x=2)+1/(x+2)(x+3)+%+...+1/(x+2003)（x+2004)=1/3x+6012

1/(x+1)(x+2)+1/(x+2)(x+3)+%+。。。+1/(x+2003)（x+2004)=1/3x+6012 1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+。1/(x+2003)-1/(x+2004)=1/3(x+2004)1/(x+1)-1/(x+2004)=1/3(x+2004)3(x+2004)-3(x+1)=(x+1)3x+6012-3x-3=x+1x=6008这里采用的是拆项法,不理解,