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Dy=√(x+2)-√(1-x)>0,y²=x+2+1-x-2√(x+2)(1-x)=3-2√[-(x+1/2)²+9/4]x∈[0,1],=> [-(x+1/2)²+9/4]∈[0,2],=>-2√[-(x+1/2)²+9/4]∈[-2√2,0],=> y²∈[3-2√2,3],=> y∈[√2-1,√3]Df(x)=(ax+1)/(x+2)=a+(1-2a)/(x+2),1/(x+2)在(-2,+∝)为减函数,则要使f(x)在(-2,+∝)为增函数,则1-2a1/2