解方程1.x(2x+7)=3(2x+7) 2.3/2x²-4x=1 3.x(3x-4)-7=2(x²

学习 时间:2026-04-07 18:19:51 阅读:2284
解方程1.x(2x+7)=3(2x+7) 2.3/2x²-4x=1 3.x(3x-4)-7=2(x²-2)+2x

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2026-04-07 18:19:51

1。x(2x+7)=3(2x+7) x(2x+7)-3(2x+7) =0(2x+7)(x-3)=0x=-7/2 x=32。3/2x²-4x=1 3x²-8x-2=0x²-8x/3=2/3x²-8x/3+16/9=2/3+16/9(x-4/3)²=22/9x=4/3+√22/3 x=4/3-√22/33。x(3x-4)-7=2(x²-2)+2x3x²-4x-7=2x²-4+2xx²-6x-3=0x²-6x+9=12(x-3)²=12x=3+2√3 x=3-2√3

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    2026-04-07 18:19:51

    1。x(2x+7)=3(2x+7) x(2x+7)-3(2x+7) =0(2x+7)(x-3)=0x=-7/2 x=32。3/2x²-4x=1 3x²-8x-2=0x²-8x/3=2/3x²-8x/3+16/9=2/3+16/9(x-4/3)²=22/9x=4/3+√22/3 x=4/3-√22/33。x(3x-4)-7=2(x²-2)+2x3x²-4x-7=2x²-4+2xx²-6x-3=0x²-6x+9=12(x-3)²=12x=3+2√3 x=3-2√3

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