设函数f(x)=x*(x-1)*(x-2)...(x-99)(x-100),则f′(0)=

因为f(x)=x*(x-1)*(x-2)。。。(x-99)(x-100)所以f(0)=0所以f′(0)=lim(x→0)[f(x)-f(0)]/(x-0)=lim(x→0)f(x)/x=lim(x→0)[x*(x-1)*(x-2)。。。(x-99)(x-100)]/x=lim(x→0)(x-1)*(x-2)。。。(x-99)(x-100)=(0-1)*(0-2)。。。(0-99)(0-100)=100!注n!=1*2*3*。。。*n（!是阶乘的意思）