已知α为锐角,且sin^2α-sinαcosα-2cos^2=0.(1)求tanα的值.(2)求sin[α-(π/3)]

1。sin^2α-sinαcosα-2cos^2= sin^2 a-cos^2 a-1/2(sin2a)-cos^2a+1-1=-cos2a-1/2(sin2a)-1=0cos2a+1/2(sin2a)=-1(1-tan^2a)/(1+tan^2a)-0。5[ 2tana/(1+tan^2a)]=-11-tan^2a-tana=-1-tan^2atana=22。已知α为锐角,则sina=2/根号5 cosa=1/根号5sina[a-(TT/3)]=sinacos60-sin60cosa=(1-根号3）/2根号5