求y=x+arctany隐函数的二阶导数

先求一阶导数,等式两边y对x求导：y'=1+(1/1+y^2)y' 移项可得：y'=(1+y^2)/y^2=1+(1/y^2)对y'继续求导可得二阶导数：y"=-2y^(-3) y'=(-2/y^3)[1+(1/y^2)]=(-2/y^3)-(2/y^5)=-2[(1/y^3)+(1/y^5)]答案仅供参考,