求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2)

显然在x趋向于0时,分子ln(1+x^2)趋向于ln1=0,而分母sin(1+x^2)趋向于sin1, 所以极限lim(x趋向于0) ln(1+x^2)/sin(1+x^2)= 0/sin1= 0