利用乘法公式进行计算(a²-b²)÷(a+b)[(a+b)²-4ab]÷(a-b)&sup

(a²-b²)÷(a+b)=[(a+b)(a-b)]÷(a+b)=a-b [(a+b)²-4ab]÷(a-b)²=[a²+2ab+b²-4ab]÷(a-b)²=[a²-2ab+b²]÷(a-b)²=(a-b)²÷(a-b)²=1 (a⁴-b⁴)÷(a²+b²)÷(a+b)=[(a²-b²)(a²+b²)]÷(a²+b²)÷(a+b)=(a²-b²)÷(a+b)=[(a-b)(a+b)]÷(a+b)=a-b 6x的5次-15x⁴+3x³-3x²+x+1除以3x²,余式为x+1 6x的5次-15x⁴+3x³-3x²+x+1-(x+1)=6x的5次-15x⁴+3x³-3x²=3x²*[2x³-5x²+x-1]所以 商=2x³-5x²+x-1