用x-1分之x-1化简(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)

学习 时间:2026-04-03 08:14:08 阅读:2543
用x-1分之x-1化简(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)

最佳回答

热心的镜子

碧蓝的哈密瓜

2026-04-03 08:14:08

=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)/(x-1)=(x^2-1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)/(x-1)=(x^4-1)(x^4+1)(x^8+1)(x^16+1)/(x-1)=。。。=(x^32-1)/(x-1)

最新回答共有2条回答

  • 威武的秋天
    回复
    2026-04-03 08:14:08

    =(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)/(x-1)=(x^2-1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)/(x-1)=(x^4-1)(x^4+1)(x^8+1)(x^16+1)/(x-1)=。。。=(x^32-1)/(x-1)

上一篇 生病的用英语怎么说?

下一篇 语文关于《范进中举》的题目