求和Sn=1/1*4+1/4*7+.1/(3n-2)(3n+1)

学习 时间:2026-06-05 05:44:24 阅读:1116
求和Sn=1/1*4+1/4*7+.1/(3n-2)(3n+1)

最佳回答

诚心的砖头

小巧的刺猬

2026-06-05 05:44:24

答:Sn=1/1*4+1/4*7+。。+1/(3n-2)(3n+1)=(1-1/4)*1/3+(1/4-1/7)*1/3+。。。+(1/(3n-2)-1/(3n+1))*1/3=(1-1/4+1/4-1/7+。。。+1/(3n-2)-1/(3n+1))*1/3=(1-1/(3n+1))*1/3=1/3-1/(9n+3)

最新回答共有2条回答

  • 乐观的芝麻
    回复
    2026-06-05 05:44:24

    答:Sn=1/1*4+1/4*7+。。+1/(3n-2)(3n+1)=(1-1/4)*1/3+(1/4-1/7)*1/3+。。。+(1/(3n-2)-1/(3n+1))*1/3=(1-1/4+1/4-1/7+。。。+1/(3n-2)-1/(3n+1))*1/3=(1-1/(3n+1))*1/3=1/3-1/(9n+3)

上一篇 Are these your ruler?的单数句是什么

下一篇 下列化学知识运用错误的是(  )