若a,b互为负倒数,a,c互为相反数且b的绝对值=2则代数式d的2平方减d乘((a+ab+c)/2)平方的值

a,b互为负倒数ab=-1a,c互为相反数a+c=0是不是|d|=2?d=2或-2,d^2=4d^2-d*[(a+c+ab)/2]^2=4-(±2)*[(-1+0)/2]^2=4-(±2)*(1/4)=4-(±1/2)所以d^2-d*[(a+c+ab)/2]^2=4+1/2=9/2或d^2-d*[(a+c+ab)/2]^2=4-1/2=7/2