如图,一束光线从点Q(0,1)出发,经x轴上点A(3/4,0)反射后,经过点P(由光线反射规律知角1=角2),

由光线反射规律知角1=角2,【过A作x轴的垂线,即为法线】所以角QAO=角PAx,k1=-k2;QA:y=k1x+b1,y=-(QO/AO)x+1=-(4/3)x+1;AP:y=k2x+b2,y=(QO/AO)x+b2=(4/3)x+b2,过A(3/4,0),0=(4/3)*(3/4)+b2,b2=-1；y=(4/3)x-1;