1.given the function f(x) = x*2 -4x -5,find the values of:

学习 时间:2026-04-03 11:27:54 阅读:4772
1.given the function f(x) = x*2 -4x -5,find the values of:a) f(k-2) b) f(x*2) - x*2 f(1)2.given two functions f(x) = x*2 -3 and g(x) = 3x-4,find the values of:a) f(k+1) -g(k-1) b) f(g(x)) c) g(f(x))3.let f(x) = 1/1-x,finda) f(f(x)) b) f(f(f(x))) c) f( 1/f(x) ) d) f (1/f(f(x)) )感激不尽!

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纯真的水杯

英勇的芹菜

2026-04-03 11:27:54

1。a) f(k-2)=(k-2)²-4(k-2)-5=k²-8k-9b) f(x²)-x²f(1)=(x²)²-4x²-5-x²(1²-4-5)=x^4-4x²-5+8x²=x^4+4x²-52。a) f(k+1)-g(k-1)=[(k+1)²-3]-[3(k-1)-4]=k²+2k-2-3k+7=k²-k+5b) f(g(x))=(3x-4)²-3=9x²-24x+13c) g(f(x))=3(x²-3)-4=3x²-133。a) f(f(x))=1/[1-(1/(1-x))]=(1-x)/(1-x-1)=(x-1)/xb) f(f(f(x)))=1/[1-((x-1)/x)]=x/[x-(x-1)]=xc) f(1/f(x))=f(1-x)=1/[1-(1-x)]=1/xd) f(1/f(f(x)))=f(x/(x-1))=1/[1-x/(x-1)]=(x-1)/(x-1-x)=1-x

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  • 正直的洋葱
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    2026-04-03 11:27:54

    1。a) f(k-2)=(k-2)²-4(k-2)-5=k²-8k-9b) f(x²)-x²f(1)=(x²)²-4x²-5-x²(1²-4-5)=x^4-4x²-5+8x²=x^4+4x²-52。a) f(k+1)-g(k-1)=[(k+1)²-3]-[3(k-1)-4]=k²+2k-2-3k+7=k²-k+5b) f(g(x))=(3x-4)²-3=9x²-24x+13c) g(f(x))=3(x²-3)-4=3x²-133。a) f(f(x))=1/[1-(1/(1-x))]=(1-x)/(1-x-1)=(x-1)/xb) f(f(f(x)))=1/[1-((x-1)/x)]=x/[x-(x-1)]=xc) f(1/f(x))=f(1-x)=1/[1-(1-x)]=1/xd) f(1/f(f(x)))=f(x/(x-1))=1/[1-x/(x-1)]=(x-1)/(x-1-x)=1-x

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