已知a=5,b=-1|5,n为自然数,你能求出a*(2n+2)·b*(2n)·b*4的值吗?

应该是这样吧?a^(2n+2)*b^(2n)*b^4a=5b=-1/5a^(2n+2)*b^(2n)*b^4=5^(2n+2)*(-1/5)^(2n+4)=5^(2n+2)*(5)^(-2n-4)=5^(2n+2-2n-4)=5^(-2)=1/25