当X≥1时,arctanx+arccox(2x/1+x2)=π/4

学习 时间:2026-04-03 14:00:19 阅读:3748
当X≥1时,arctanx+arccox(2x/1+x2)=π/4

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笑点低的哈密瓜

苗条的萝莉

2026-04-03 14:00:19

原式是:arctanx+arccos(2x/1+x2)=π/4?①sinarctanx=x/(√(1+x^2));cosarctanx=1/(√(1+x^2));cosarccos(2x/1+x2)=2x/(1+x^2);sinarccos(2x/1+x2)=(1-x^2)/(1+x^2);①式两边求sin得:x/(√(1+x^2))*2x/(1+x^2)+1/(√(1+x^2))*(1-x^2)/(1+x^2)=√2/2;即2x^2+1-x^2=√(1+x^2)*(1+x^2)*√2/2;√(1+x^2)=√2;X=1

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  • 眯眯眼的豆芽
    回复
    2026-04-03 14:00:19

    原式是:arctanx+arccos(2x/1+x2)=π/4?①sinarctanx=x/(√(1+x^2));cosarctanx=1/(√(1+x^2));cosarccos(2x/1+x2)=2x/(1+x^2);sinarccos(2x/1+x2)=(1-x^2)/(1+x^2);①式两边求sin得:x/(√(1+x^2))*2x/(1+x^2)+1/(√(1+x^2))*(1-x^2)/(1+x^2)=√2/2;即2x^2+1-x^2=√(1+x^2)*(1+x^2)*√2/2;√(1+x^2)=√2;X=1

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