求函数y=(x^4+x^2+5)/(x^2+1)^2的最大值与最小值

学习 时间:2026-09-28 16:37:52 阅读:4262
求函数y=(x^4+x^2+5)/(x^2+1)^2的最大值与最小值

最佳回答

端庄的过客

暴躁的秋天

2026-09-28 16:37:52

y=(x^4+x^2+5)/(x^4+2x^2+1) =(x^4+2x^2+1-x^2+4)/(x^4+2x^2+1) =1+(4-x^2)/(x^4+2x^2+1) =1+(5-(x^2+1))/(x^2+1)^2 =1-1/(x^2+1)+5/(x^2+1)^2令t=1/(x^2+1) ,0

最新回答共有2条回答

  • 时尚的小馒头
    回复
    2026-09-28 16:37:52

    y=(x^4+x^2+5)/(x^4+2x^2+1) =(x^4+2x^2+1-x^2+4)/(x^4+2x^2+1) =1+(4-x^2)/(x^4+2x^2+1) =1+(5-(x^2+1))/(x^2+1)^2 =1-1/(x^2+1)+5/(x^2+1)^2令t=1/(x^2+1) ,0

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