若方程组2x+3y=4,3x+2y=2m-3的解满足x+y=1/5,则m=()(要标准过程!)

学习 时间:2026-04-07 23:30:18 阅读:2172
若方程组2x+3y=4,3x+2y=2m-3的解满足x+y=1/5,则m=()(要标准过程!)

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欣慰的纸鹤

平淡的天空

2026-04-07 23:30:18

2x+3y=4x+y=1/5联立得y=18/5x=-17/5代入3x+2y=2m-3得2m-3=-32m=0m=0

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  • 跳跃的裙子
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    2026-04-07 23:30:18

    2x+3y=4x+y=1/5联立得y=18/5x=-17/5代入3x+2y=2m-3得2m-3=-32m=0m=0

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