解方程1/(x+1)(x+2)+1/(x+2)(x+3)+.+1/(x+2005)(x+2006)=1/2x+4012

学习 时间:2026-05-30 12:42:01 阅读:6589
解方程1/(x+1)(x+2)+1/(x+2)(x+3)+.+1/(x+2005)(x+2006)=1/2x+4012

最佳回答

潇洒的冥王星

狂野的小蘑菇

2026-05-30 12:42:01

1/(x+1)(x+2)+1/(x+2)(x+3)+。+1/(x+2005)(x+2006)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+。+1/(x+2005)-1/(x+2006)=1/(x+1)-1/(x+2006)=2005/(x+1)(x+2006)即原式化为:2005/(x+1)(x+2006)=1/2(x+2006)解得x=4009

最新回答共有2条回答

  • 高贵的哑铃
    回复
    2026-05-30 12:42:01

    1/(x+1)(x+2)+1/(x+2)(x+3)+。+1/(x+2005)(x+2006)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+。+1/(x+2005)-1/(x+2006)=1/(x+1)-1/(x+2006)=2005/(x+1)(x+2006)即原式化为:2005/(x+1)(x+2006)=1/2(x+2006)解得x=4009

上一篇 “再不回头”原意指什么?

下一篇 太后和皇后的区别