解方程1/(x+1)(x+2)+1/(x+2)(x+3)+.+1/(x+2005)(x+2006)=1/2x+4012

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解方程1/(x+1)(x+2)+1/(x+2)(x+3)+.+1/(x+2005)(x+2006)=1/2x+4012

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负责的金针菇

瘦瘦的盼望

2026-08-14 05:45:33

1/(x+1)(x+2)+1/(x+2)(x+3)+。+1/(x+2005)(x+2006)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+。+1/(x+2005)-1/(x+2006)=1/(x+1)-1/(x+2006)=2005/(x+1)(x+2006)即原式化为:2005/(x+1)(x+2006)=1/2(x+2006)解得x=4009

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  • 清秀的大白
    回复
    2026-08-14 05:45:33

    1/(x+1)(x+2)+1/(x+2)(x+3)+。+1/(x+2005)(x+2006)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+。+1/(x+2005)-1/(x+2006)=1/(x+1)-1/(x+2006)=2005/(x+1)(x+2006)即原式化为:2005/(x+1)(x+2006)=1/2(x+2006)解得x=4009

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