分式化简:[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/(x-4)/(x^3-2x^2)

学习 时间:2026-04-02 12:24:34 阅读:4537
分式化简:[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/(x-4)/(x^3-2x^2)

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疯狂的小刺猬

忧心的衬衫

2026-04-02 12:24:34

[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/(x-4)/(x^3-2x^2)=(x+2)x^2(x-2)/[x(x-2)(x-4)]-(x-1)x^2(x-2)/[(x-2)^2(x-4)]=(x+2)x/(x-4)-(x-1)x^2/[(x-2)(x-4)]=(x^3-4x-x^3+x^2)/[(x-2)(x-4)]=x(x-4)/[(x-2)(x-4)]=x/(x-2)

最新回答共有2条回答

  • 酷炫的舞蹈
    回复
    2026-04-02 12:24:34

    [(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/(x-4)/(x^3-2x^2)=(x+2)x^2(x-2)/[x(x-2)(x-4)]-(x-1)x^2(x-2)/[(x-2)^2(x-4)]=(x+2)x/(x-4)-(x-1)x^2/[(x-2)(x-4)]=(x^3-4x-x^3+x^2)/[(x-2)(x-4)]=x(x-4)/[(x-2)(x-4)]=x/(x-2)

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