利用极限存在准则证明lim(n—>无穷)n^2[1/(n^2+1)^2+2/(n^2+2)^2+...+n/(n^2+n

学习 时间:2026-06-05 04:35:40 阅读:5301
利用极限存在准则证明lim(n—>无穷)n^2[1/(n^2+1)^2+2/(n^2+2)^2+...+n/(n^2+n)^2]=1/2

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执着的冬天

孝顺的大碗

2026-06-05 04:35:40

1。n^2[1/(n^2+1)^2+2/(n^2+2)^2+。。。+n/(n^2+n)^2]≥ n^2[1/(n^2+n)^2+2/(n^2+n)^2+。。。+n/(n^2+n)^2]= n^2[1+2+。。。+n]/[(n^2+n)^2]= n^2[n(n+1)/2]/[(n^2+n)^2]= (1/2)[n^4+n^3]/[n^4+2n^3+n^2](1/2)[n^4+n^3]/[n^4+2n^3+n^2]中令n->∞,极限是1/22。n^2[1/(n^2+1)^2+2/(n^2+2)^2+。。。+n/(n^2+n)^2]≤ n^2[1/(n^2+1)^2+2/(n^2+1)^2+。。。+n/(n^2+1)^2]= n^2[1+2+。。。+n]/[(n^2+1)^2]= n^2[n(n+1)/2]/[(n^2+1)^2]= (1/2)[n^4+n^3]/[n^4+2n^3+1](1/2)[n^4+n^3]/[n^4+2n^3+1]中令n->∞,极限是1/2根据夹逼定理(准则),知道极限存在,并且极限是1/2。

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  • 朴实的洋葱
    回复
    2026-06-05 04:35:40

    1。n^2[1/(n^2+1)^2+2/(n^2+2)^2+。。。+n/(n^2+n)^2]≥ n^2[1/(n^2+n)^2+2/(n^2+n)^2+。。。+n/(n^2+n)^2]= n^2[1+2+。。。+n]/[(n^2+n)^2]= n^2[n(n+1)/2]/[(n^2+n)^2]= (1/2)[n^4+n^3]/[n^4+2n^3+n^2](1/2)[n^4+n^3]/[n^4+2n^3+n^2]中令n->∞,极限是1/22。n^2[1/(n^2+1)^2+2/(n^2+2)^2+。。。+n/(n^2+n)^2]≤ n^2[1/(n^2+1)^2+2/(n^2+1)^2+。。。+n/(n^2+1)^2]= n^2[1+2+。。。+n]/[(n^2+1)^2]= n^2[n(n+1)/2]/[(n^2+1)^2]= (1/2)[n^4+n^3]/[n^4+2n^3+1](1/2)[n^4+n^3]/[n^4+2n^3+1]中令n->∞,极限是1/2根据夹逼定理(准则),知道极限存在,并且极限是1/2。

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