解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)

学习 时间:2026-04-02 12:06:49 阅读:9734
解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)要求用到规律:1/n(n+1)=1/n-1/(n+1)

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难过的小土豆

痴情的龙猫

2026-04-02 12:06:49

1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)1/(x-3)-1/(x-4)=1/(x-4)1/(x-3)=2/(x-4)2(x-3)=x-42x-6=x-4x=2检验是增根所以原分式方程无解

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  • 独特的大地
    回复
    2026-04-02 12:06:49

    1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)1/(x-3)-1/(x-4)=1/(x-4)1/(x-3)=2/(x-4)2(x-3)=x-42x-6=x-4x=2检验是增根所以原分式方程无解

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