解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)

学习 时间:2026-08-14 21:47:33 阅读:2510
解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)要求用到规律:1/n(n+1)=1/n-1/(n+1)

最佳回答

炙热的衬衫

笑点低的超短裙

2026-08-14 21:47:33

1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)1/(x-3)-1/(x-4)=1/(x-4)1/(x-3)=2/(x-4)2(x-3)=x-42x-6=x-4x=2检验是增根所以原分式方程无解

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  • 雪白的八宝粥
    回复
    2026-08-14 21:47:33

    1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)1/(x-3)-1/(x-4)=1/(x-4)1/(x-3)=2/(x-4)2(x-3)=x-42x-6=x-4x=2检验是增根所以原分式方程无解

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