解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)

学习 时间:2026-11-15 15:48:19 阅读:6321
解方程1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)要求用到规律:1/n(n+1)=1/n-1/(n+1)

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2026-11-15 15:48:19

1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)1/(x-3)-1/(x-4)=1/(x-4)1/(x-3)=2/(x-4)2(x-3)=x-42x-6=x-4x=2检验是增根所以原分式方程无解

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  • 精明的大炮
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    2026-11-15 15:48:19

    1/(x-2)(x-3)-3/(x-1)(x-4)+1/(x-1)(x-2)=1/(x-4)1/(x-3)-1/(x-2)-1/(x-4)+1/(x-1)+1/(x-2)-1/(x-1)=1/(x-4)1/(x-3)-1/(x-4)=1/(x-4)1/(x-3)=2/(x-4)2(x-3)=x-42x-6=x-4x=2检验是增根所以原分式方程无解

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