y=sin(x+π/3)+2定义域怎么求?

y∈[1,3]当y=1时,sin(x+π/3)=-1,x+π/3=2kπ-π/2,x=kπ-5π/12,k∈Z当y=3时,sin(x+π/3)=1,x+π/3=2kπ+π/2,x=kπ+π/12,k∈Z ∴当x∈[kπ-5π/12,kπ+π/12]时,y∈[1,3]