若x²+3x-1/3=0 则代数式x-3/3x²-6x÷(x+2-5/x-2)的值

若x²+3x-1/3=0 则代数式x-3/3x²-6x÷(x+2-5/x-2)的值(x-3)/(3x²-6x)÷[(x+2)-5/(x-2)]=(x-3)/3x(x-2)÷[(x²-4-5）/(x-2)]=[(x-3)/3x(x-2)]÷[(x-3)(x+3)/(x-2)]=1/3x÷(x+3)=1/3(x²+3x)=1/(3×1/3)=1