如图2-1-2,直线AB.CD相交于点O,OE平分∠BOD,且∠AOC=∠AOD-80°,求∠AOE的度数

学习时间:2026-09-29 03:22:36 阅读：3561

如图2-1-2,直线AB.CD相交于点O,OE平分∠BOD,且∠AOC=∠AOD-80°,求∠AOE的度数图是我复制的,OF不要

苹果鞋垫

2026-09-29 03:22:36

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。∠AOC + ∠AOD = 180°∠AOC=∠AOD-80°解得：∠AOC = 50°,∠AOD = 130°∠DOE = 1/2 * ∠BOD = 1/2 * ∠AOC = 25°∠AOE = ∠AOD + ∠DOE = 155°